What are the solutions to the equation y^2-3y-9=0 ?

The solutions to the equation y^2-3y-9=0 are y=(3+3sqrt(5))/2 ,y=(3-3sqrt(5))/2

Find the zeros of y^2-3y-9=0

The zeros of y^2-3y-9=0 are y=(3+3sqrt(5))/2 ,y=(3-3sqrt(5))/2

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y^{2} - 3 y - 9 = 0

y = \frac{3 + 3 5}{2}, y = \frac{3 - 3 5}{2}

Decimal Notation

y = 4.85410 \dots, y = - 1.85410 \dots

Solution steps

y^{2} - 3 y - 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 9) = 35

y_{1, 2} = \frac{- ( - 3 ) \pm 3 5}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 3 ) + 3 5}{2 \cdot 1}, y_{2} = \frac{- ( - 3 ) - 3 5}{2 \cdot 1}

y = \frac{- ( - 3 ) + 3 5}{2 \cdot 1} : \frac{3 + 3 5}{2}

y = \frac{- ( - 3 ) - 3 5}{2 \cdot 1} : \frac{3 - 3 5}{2}

The solutions to the quadratic equation are:

y = \frac{3 + 3 5}{2}, y = \frac{3 - 3 5}{2}

3 z + 1 = 2 z

- \frac{1}{5} - 1

\frac{x}{5} + \frac{x}{3} + 7 = 15

3 \cdot 1063

\frac{15}{7} + \frac{8}{9}

What are the solutions to the equation y^2-3y-9=0 ?
The solutions to the equation y^2-3y-9=0 are y=(3+3sqrt(5))/2 ,y=(3-3sqrt(5))/2
Find the zeros of y^2-3y-9=0
The zeros of y^2-3y-9=0 are y=(3+3sqrt(5))/2 ,y=(3-3sqrt(5))/2