What is |(h-66.5)/(2.8)|<= 1 ?

The solution to |(h-66.5)/(2.8)|<= 1 is 63.7<= h<= 69.3

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|(h-66.5)/(2.8)|<= 1

\frac{h - 66.5}{2.8} \leq 1

63.7 \leq h \leq 69.3

Interval Notation

[63.7, 69.3]

Solution steps

\frac{h - 66.5}{2.8} \leq 1

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 1 \leq \frac{h - 66.5}{2.8} \leq 1

\frac{h - 66.5}{2.8} \geq - 1 and \frac{h - 66.5}{2.8} \leq 1

h \geq 63.7 and h \leq 69.3

Merge Overlapping Intervals

63.7 \leq h \leq 69.3

\frac{2 - ln ( x )}{2 x x}

\frac{4}{7} x = 20

\frac{1000}{π \cdot 0.03 \cdot 0.06}

3 k^{2} + 1 k = - 10

\frac{( ( x + h ) ^{(\frac{3}{2})} - x ^{\frac{3}{2}} )}{h}

What is |(h-66.5)/(2.8)|<= 1 ?
The solution to |(h-66.5)/(2.8)|<= 1 is 63.7<= h<= 69.3