What are the solutions to the equation (x-2)(2x+5)=2x+5 ?

The solutions to the equation (x-2)(2x+5)=2x+5 are x=3,x=-5/2

Find the zeros of (x-2)(2x+5)=2x+5

The zeros of (x-2)(2x+5)=2x+5 are x=3,x=-5/2

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(x - 2) (2 x + 5) = 2 x + 5

x = 3, x = - \frac{5}{2}

Decimal Notation

x = 3, x = - 2.5

Solution steps

(x - 2) (2 x + 5) = 2 x + 5

Expand

(x - 2) (2 x + 5) : 2 x^{2} + x - 10

2 x^{2} + x - 10 = 2 x + 5

Move

5

to the left side

2 x^{2} + x - 15 = 2 x

Move

2 x

to the left side

2 x^{2} - x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 15) = 11

x_{1, 2} = \frac{- ( - 1 ) \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 11}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 11}{2 \cdot 2}

x = \frac{- ( - 1 ) + 11}{2 \cdot 2} : 3

x = \frac{- ( - 1 ) - 11}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 3, x = - \frac{5}{2}

(x - 5)^{2} = 81

- 4 (3^{2} - 8) + 1

y - 3 < 5 y + 1

∣ u ∣ = 0

5.56 E - 10 = \frac{x ^{2}}{0.62}

What are the solutions to the equation (x-2)(2x+5)=2x+5 ?
The solutions to the equation (x-2)(2x+5)=2x+5 are x=3,x=-5/2
Find the zeros of (x-2)(2x+5)=2x+5
The zeros of (x-2)(2x+5)=2x+5 are x=3,x=-5/2