What is 8/5+9/4 (6/7-8/9)\div 3/2 ?

The solution to 8/5+9/4 (6/7-8/9)\div 3/2 is 1 58/105

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8/5+9/4 (6/7-8/9)\div 3/2

\frac{8}{5} + \frac{9}{4} (\frac{6}{7} - \frac{8}{9}) \div \frac{3}{2}

1 \frac{58}{105}

Solution steps

\frac{8}{5} + \frac{9}{4} (\frac{6}{7} - \frac{8}{9}) \div \frac{3}{2}

Follow the PEMDAS order of operations

Calculate within parentheses

(\frac{6}{7} - \frac{8}{9}) : - \frac{2}{63}

= \frac{8}{5} + \frac{9}{4} (- \frac{2}{63}) \div \frac{3}{2}

Multiply and divide (left to right)

\frac{9}{4} (- \frac{2}{63}) \div \frac{3}{2} : \frac{1}{21}

= \frac{8}{5} - \frac{1}{21}

Add and subtract (left to right)

\frac{8}{5} - \frac{1}{21} : \frac{163}{105}

= \frac{163}{105}

Convert improper fractions to mixed numbers:

\frac{163}{105} = 1 \frac{58}{105}

= 1 \frac{58}{105}

0 = x^{2} + 2 \cdot 0.53179851 \cdot (32)

x^{2} - x - 12

\frac{9 ^{- 2}}{9 ^{- 4}}

- \frac{1}{\frac{1}{3}}

∣ x ∣ > 12

What is 8/5+9/4 (6/7-8/9)\div 3/2 ?
The solution to 8/5+9/4 (6/7-8/9)\div 3/2 is 1 58/105