What are the solutions to the equation x^2+x^2=36 ?

The solutions to the equation x^2+x^2=36 are x=3sqrt(2),x=-3sqrt(2)

Find the zeros of x^2+x^2=36

The zeros of x^2+x^2=36 are x=3sqrt(2),x=-3sqrt(2)

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x^{2} + x^{2} = 36

x = 32, x = - 32

Solution steps

x^{2} + x^{2} = 36

Add similar elements:

x^{2} + x^{2} = 2 x^{2}

2 x^{2} = 36

Divide both sides by

2

x^{2} = 18

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 18, x = - 18

18 = 32

- 18 = - 32

x = 32, x = - 32

\frac{3 ^{3}}{3 !}

3 (n + 1) = 15

- 6 g^{2} + 3 g + 5 = 0

1 + \frac{10 x}{11} - \frac{1}{10} (x + 11) \geq x

\frac{\frac{1}{x} + \frac{1}{y}}{\frac{1}{x} - \frac{1}{y}}

What are the solutions to the equation x^2+x^2=36 ?
The solutions to the equation x^2+x^2=36 are x=3sqrt(2),x=-3sqrt(2)
Find the zeros of x^2+x^2=36
The zeros of x^2+x^2=36 are x=3sqrt(2),x=-3sqrt(2)