What are the solutions to the equation x^2-9x+18=0 ?

The solutions to the equation x^2-9x+18=0 are x=6,x=3

Find the zeros of x^2-9x+18=0

The zeros of x^2-9x+18=0 are x=6,x=3

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x^{2} - 9 x + 18 = 0

x = 6, x = 3

Solution steps

x^{2} - 9 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 18 = 3

x_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 1}

x = \frac{- ( - 9 ) + 3}{2 \cdot 1} : 6

x = \frac{- ( - 9 ) - 3}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 6, x = 3

4 x^{2} + 3 x + 1 = - 2

- \frac{5}{2 ( \frac{1}{16} ) ^{\frac{3}{2}}}

10 x + 24 < 16 x + 12

2 - x \leq 1

n^{2} - 14 n + 24

What are the solutions to the equation x^2-9x+18=0 ?
The solutions to the equation x^2-9x+18=0 are x=6,x=3
Find the zeros of x^2-9x+18=0
The zeros of x^2-9x+18=0 are x=6,x=3