What are the solutions to the equation 4k^2+12k-11=5 ?

The solutions to the equation 4k^2+12k-11=5 are k=1,k=-4

Find the zeros of 4k^2+12k-11=5

The zeros of 4k^2+12k-11=5 are k=1,k=-4

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4 k^{2} + 12 k - 11 = 5

k = 1, k = - 4

Solution steps

4 k^{2} + 12 k - 11 = 5

Move

5

to the left side

4 k^{2} + 12 k - 16 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 16 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 16) = 20

k_{1, 2} = \frac{- 12 \pm 20}{2 \cdot 4}

Separate the solutions

k_{1} = \frac{- 12 + 20}{2 \cdot 4}, k_{2} = \frac{- 12 - 20}{2 \cdot 4}

k = \frac{- 12 + 20}{2 \cdot 4} : 1

k = \frac{- 12 - 20}{2 \cdot 4} : - 4

The solutions to the quadratic equation are:

k = 1, k = - 4

(63)^{2} + (63)^{2} = c^{2}

7 \cdot 6

- (\frac{5}{3})^{3}

∣ x ∣ + ∣ x - 1 ∣ = - 3

\frac{4}{3} b - 11 = 25

What are the solutions to the equation 4k^2+12k-11=5 ?
The solutions to the equation 4k^2+12k-11=5 are k=1,k=-4
Find the zeros of 4k^2+12k-11=5
The zeros of 4k^2+12k-11=5 are k=1,k=-4