What are the solutions to the equation -2x^2-12x-9=0 ?

The solutions to the equation -2x^2-12x-9=0 are x=-(3(2+sqrt(2)))/2 ,x=-(3(2-sqrt(2)))/2

Find the zeros of -2x^2-12x-9=0

The zeros of -2x^2-12x-9=0 are x=-(3(2+sqrt(2)))/2 ,x=-(3(2-sqrt(2)))/2

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- 2 x^{2} - 12 x - 9 = 0

x = - \frac{3 ( 2 + 2 )}{2}, x = - \frac{3 ( 2 - 2 )}{2}

Decimal Notation

x = - 5.12132 \dots, x = - 0.87867 \dots

Solution steps

- 2 x^{2} - 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 2 ) ( - 9 )}{2 ( - 2 )}

(- 12)^{2} - 4 (- 2) (- 9) = 62

x_{1, 2} = \frac{- ( - 12 ) \pm 6 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 2}{2 ( - 2 )}, x_{2} = \frac{- ( - 12 ) - 6 2}{2 ( - 2 )}

x = \frac{- ( - 12 ) + 6 2}{2 ( - 2 )} : - \frac{3 ( 2 + 2 )}{2}

x = \frac{- ( - 12 ) - 6 2}{2 ( - 2 )} : - \frac{3 ( 2 - 2 )}{2}

The solutions to the quadratic equation are:

x = - \frac{3 ( 2 + 2 )}{2}, x = - \frac{3 ( 2 - 2 )}{2}

\frac{3 ^{4} \cdot 27 \cdot 64}{2 ^{4} \cdot 2 \cdot 2 ^{3}}

- 3 x - 2 < 0 or x - 2 < - 5

ln (8) = 2 x + 5

2 (0) - y = 1

3 x^{2} - 8 x - 7 = 0

What are the solutions to the equation -2x^2-12x-9=0 ?
The solutions to the equation -2x^2-12x-9=0 are x=-(3(2+sqrt(2)))/2 ,x=-(3(2-sqrt(2)))/2
Find the zeros of -2x^2-12x-9=0
The zeros of -2x^2-12x-9=0 are x=-(3(2+sqrt(2)))/2 ,x=-(3(2-sqrt(2)))/2