What are the solutions to the equation x(x-3)+3=0 ?

The solutions to the equation x(x-3)+3=0 are x= 3/2+i(sqrt(3))/2 ,x= 3/2-i(sqrt(3))/2

Find the zeros of x(x-3)+3=0

The zeros of x(x-3)+3=0 are x= 3/2+i(sqrt(3))/2 ,x= 3/2-i(sqrt(3))/2

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x (x - 3) + 3 = 0

x = \frac{3}{2} + i \frac{3}{2}, x = \frac{3}{2} - i \frac{3}{2}

Solution steps

x (x - 3) + 3 = 0

Expand

x (x - 3) + 3 : x^{2} - 3 x + 3

x^{2} - 3 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

(- 3)^{2} - 4 \cdot 1 \cdot 3 : 3 i

x_{1, 2} = \frac{- ( - 3 ) \pm 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3 i}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3 i}{2 \cdot 1} : \frac{3}{2} + i \frac{3}{2}

x = \frac{- ( - 3 ) - 3 i}{2 \cdot 1} : \frac{3}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{3}{2}, x = \frac{3}{2} - i \frac{3}{2}

\frac{x - 6}{8} \geq \frac{x - 3}{12} + \frac{1}{24}

(\frac{1}{a})^{2}

\frac{( x ^{\frac{1}{2}} \cdot y ) ^{2}}{x ^{2}}

(\frac{1}{2})^{- 5}

- (12 x)^{- 2}

What are the solutions to the equation x(x-3)+3=0 ?
The solutions to the equation x(x-3)+3=0 are x= 3/2+i(sqrt(3))/2 ,x= 3/2-i(sqrt(3))/2
Find the zeros of x(x-3)+3=0
The zeros of x(x-3)+3=0 are x= 3/2+i(sqrt(3))/2 ,x= 3/2-i(sqrt(3))/2