What are the solutions to the equation n^2+8n-11=-5 ?

The solutions to the equation n^2+8n-11=-5 are n=-4+sqrt(22),n=-4-sqrt(22)

Find the zeros of n^2+8n-11=-5

The zeros of n^2+8n-11=-5 are n=-4+sqrt(22),n=-4-sqrt(22)

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n^{2} + 8 n - 11 = - 5

n = - 4 + 22, n = - 4 - 22

Decimal Notation

n = 0.69041 \dots, n = - 8.69041 \dots

Solution steps

n^{2} + 8 n - 11 = - 5

Move

5

to the left side

n^{2} + 8 n - 6 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 6) = 222

n_{1, 2} = \frac{- 8 \pm 2 22}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 8 + 2 22}{2 \cdot 1}, n_{2} = \frac{- 8 - 2 22}{2 \cdot 1}

n = \frac{- 8 + 2 22}{2 \cdot 1} : - 4 + 22

n = \frac{- 8 - 2 22}{2 \cdot 1} : - 4 - 22

The solutions to the quadratic equation are:

n = - 4 + 22, n = - 4 - 22

∣ 7 x + 3 ∣ - 11 = - 5

\frac{q ^{\frac{3}{5}}}{q ^{\frac{2}{5}}}

\frac{3 2 - 2 3}{3 2 + 2 3}

\frac{x}{3} + \frac{1}{4} = 2

9 q - (q - 2) = 6 q + 2 (q + 1)

What are the solutions to the equation n^2+8n-11=-5 ?
The solutions to the equation n^2+8n-11=-5 are n=-4+sqrt(22),n=-4-sqrt(22)
Find the zeros of n^2+8n-11=-5
The zeros of n^2+8n-11=-5 are n=-4+sqrt(22),n=-4-sqrt(22)