What are the solutions to the equation x^2-13x+22=0 ?

The solutions to the equation x^2-13x+22=0 are x=11,x=2

Find the zeros of x^2-13x+22=0

The zeros of x^2-13x+22=0 are x=11,x=2

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x^{2} - 13 x + 22 = 0

x = 11, x = 2

Solution steps

x^{2} - 13 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 22 = 9

x_{1, 2} = \frac{- ( - 13 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 9}{2 \cdot 1}

x = \frac{- ( - 13 ) + 9}{2 \cdot 1} : 11

x = \frac{- ( - 13 ) - 9}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 11, x = 2

856

3 < - 2 x - 1 \leq 7

- (\frac{1}{2})^{- 2}

3 x^{2} - 30 x = 69

\frac{\frac{2}{5} + \frac{1}{2}}{\frac{1}{10} + \frac{2}{10}}

What are the solutions to the equation x^2-13x+22=0 ?
The solutions to the equation x^2-13x+22=0 are x=11,x=2
Find the zeros of x^2-13x+22=0
The zeros of x^2-13x+22=0 are x=11,x=2