What are the solutions to the equation 3n^2-29n+855=0 ?

The solutions to the equation 3n^2-29n+855=0 are n= 29/6+i(sqrt(9419))/6 ,n= 29/6-i(sqrt(9419))/6

Find the zeros of 3n^2-29n+855=0

The zeros of 3n^2-29n+855=0 are n= 29/6+i(sqrt(9419))/6 ,n= 29/6-i(sqrt(9419))/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 n^{2} - 29 n + 855 = 0

n = \frac{29}{6} + i \frac{9419}{6}, n = \frac{29}{6} - i \frac{9419}{6}

Solution steps

3 n^{2} - 29 n + 855 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 3 \cdot 855}{2 \cdot 3}

Simplify

(- 29)^{2} - 4 \cdot 3 \cdot 855 : 9419 i

n_{1, 2} = \frac{- ( - 29 ) \pm 9419 i}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- ( - 29 ) + 9419 i}{2 \cdot 3}, n_{2} = \frac{- ( - 29 ) - 9419 i}{2 \cdot 3}

n = \frac{- ( - 29 ) + 9419 i}{2 \cdot 3} : \frac{29}{6} + i \frac{9419}{6}

n = \frac{- ( - 29 ) - 9419 i}{2 \cdot 3} : \frac{29}{6} - i \frac{9419}{6}

The solutions to the quadratic equation are:

n = \frac{29}{6} + i \frac{9419}{6}, n = \frac{29}{6} - i \frac{9419}{6}

x^{2} + 9 = ∣ x ∣ + 3

e^{- x^{2}} \cdot e^{x^{2}}

5 x^{2} + 29 x + 20

3 (x + 1) (x - 1) + 7 x = 5 - 3 x

x e^{- x^{2}}

What are the solutions to the equation 3n^2-29n+855=0 ?
The solutions to the equation 3n^2-29n+855=0 are n= 29/6+i(sqrt(9419))/6 ,n= 29/6-i(sqrt(9419))/6
Find the zeros of 3n^2-29n+855=0
The zeros of 3n^2-29n+855=0 are n= 29/6+i(sqrt(9419))/6 ,n= 29/6-i(sqrt(9419))/6