What are the solutions to the equation x^2+8x+15=1x+72 ?

The solutions to the equation x^2+8x+15=1x+72 are x=(-7+sqrt(277))/2 ,x=(-7-sqrt(277))/2

Find the zeros of x^2+8x+15=1x+72

The zeros of x^2+8x+15=1x+72 are x=(-7+sqrt(277))/2 ,x=(-7-sqrt(277))/2

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x^{2} + 8 x + 15 = 1 x + 72

x = \frac{- 7 + 277}{2}, x = \frac{- 7 - 277}{2}

Decimal Notation

x = 4.82165 \dots, x = - 11.82165 \dots

Solution steps

x^{2} + 8 x + 15 = 1 \cdot x + 72

Refine

x^{2} + 8 x + 15 = x + 72

Move

72

to the left side

x^{2} + 8 x - 57 = x

Move

x

to the left side

x^{2} + 7 x - 57 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 57 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 57) = 277

x_{1, 2} = \frac{- 7 \pm 277}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 277}{2 \cdot 1}, x_{2} = \frac{- 7 - 277}{2 \cdot 1}

x = \frac{- 7 + 277}{2 \cdot 1} : \frac{- 7 + 277}{2}

x = \frac{- 7 - 277}{2 \cdot 1} : \frac{- 7 - 277}{2}

The solutions to the quadratic equation are:

x = \frac{- 7 + 277}{2}, x = \frac{- 7 - 277}{2}

m + m^{2}

x^{4} y^{2} + x^{4} y^{4}

\frac{x}{x + y} + \frac{y}{x - y}

2 (x + 5) = 3 x + 1

\frac{2}{5} (x - 1) + \frac{5}{2} (x + 2) = \frac{3}{4} (x - 2)

What are the solutions to the equation x^2+8x+15=1x+72 ?
The solutions to the equation x^2+8x+15=1x+72 are x=(-7+sqrt(277))/2 ,x=(-7-sqrt(277))/2
Find the zeros of x^2+8x+15=1x+72
The zeros of x^2+8x+15=1x+72 are x=(-7+sqrt(277))/2 ,x=(-7-sqrt(277))/2