What are the solutions to the equation 3(m-1)^2-16(m-1)+5=0 ?

The solutions to the equation 3(m-1)^2-16(m-1)+5=0 are m=6,m= 4/3

Find the zeros of 3(m-1)^2-16(m-1)+5=0

The zeros of 3(m-1)^2-16(m-1)+5=0 are m=6,m= 4/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 (m - 1)^{2} - 16 (m - 1) + 5 = 0

m = 6, m = \frac{4}{3}

Decimal Notation

m = 6, m = 1.33333 \dots

Solution steps

3 (m - 1)^{2} - 16 (m - 1) + 5 = 0

Expand

3 (m - 1)^{2} - 16 (m - 1) + 5 : 3 m^{2} - 22 m + 24

3 m^{2} - 22 m + 24 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 3 \cdot 24}{2 \cdot 3}

(- 22)^{2} - 4 \cdot 3 \cdot 24 = 14

m_{1, 2} = \frac{- ( - 22 ) \pm 14}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- ( - 22 ) + 14}{2 \cdot 3}, m_{2} = \frac{- ( - 22 ) - 14}{2 \cdot 3}

m = \frac{- ( - 22 ) + 14}{2 \cdot 3} : 6

m = \frac{- ( - 22 ) - 14}{2 \cdot 3} : \frac{4}{3}

The solutions to the quadratic equation are:

m = 6, m = \frac{4}{3}

\frac{x + 1}{x - 6} < 7

x^{2} - 3 = 10 x - 28

4 (3 + w) - w = 6 + 3 (w + 2)

(3 x - 1) (2 x + 3) > (2 x + 1) (3 x + 2)

(- 5 + x)^{2} - 25

What are the solutions to the equation 3(m-1)^2-16(m-1)+5=0 ?
The solutions to the equation 3(m-1)^2-16(m-1)+5=0 are m=6,m= 4/3
Find the zeros of 3(m-1)^2-16(m-1)+5=0
The zeros of 3(m-1)^2-16(m-1)+5=0 are m=6,m= 4/3