What is factor 2w^2+7w+3 ?

The solution to factor 2w^2+7w+3 is (2w+1)(w+3)

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factor 2w^2+7w+3

factor

2 w^{2} + 7 w + 3

(2 w + 1) (w + 3)

Solution steps

2 w^{2} + 7 w + 3

Break the expression into groups

= (2 w^{2} + w) + (6 w + 3)

Factor out

w

from

2 w^{2} + w : w (2 w + 1)

Factor out

3

from

6 w + 3 : 3 (2 w + 1)

= w (2 w + 1) + 3 (2 w + 1)

Factor out common term

2 w + 1

= (2 w + 1) (w + 3)

- 3 < 2 x - 1 \leq 7

- 2 x^{2} + x - 1 \geq 0

- 15 + 3 x = 7

\frac{4 ( x + h ) ^{2} - 4 ( x ) ^{2}}{h}

3^{\frac{5}{4}}