What is (-6x^8y^{-6}z^0)/(1x^{-1)y^{-6}z^5} ?

The solution to (-6x^8y^{-6}z^0)/(1x^{-1)y^{-6}z^5} is -(6x^9)/(z^5)

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simplify (-6x^8y^{-6}z^0)/(1x^{-1)y^{-6}z^5}

simplify

\frac{- 6 x ^{8} y ^{- 6} z ^{0}}{1 x ^{- 1} y ^{- 6} z ^{5}}

- \frac{6 x ^{9}}{z ^{5}}

Solution steps

\frac{- 6 x ^{8} y ^{- 6} z ^{0}}{1 \cdot x ^{- 1} y ^{- 6} z ^{5}}

Simplify

\frac{- 6 x ^{8} y ^{- 6} z ^{0}}{1 \cdot x ^{- 1} y ^{- 6} z ^{5}} : \frac{- 6 x ^{8} y ^{- 6}}{x ^{- 1} y ^{- 6} z ^{5}}

= \frac{- 6 x ^{8} y ^{- 6}}{x ^{- 1} y ^{- 6} z ^{5}}

Cancel the common factor:

y^{- 6}

= \frac{- 6 x ^{8}}{x ^{- 1} z ^{5}}

Simplify

\frac{x ^{8}}{x ^{- 1}} : x^{9}

= \frac{- 6 x ^{9}}{z ^{5}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{6 x ^{9}}{z ^{5}}

9 x^{2} + 42 x y + 49 y^{2}

2 = a (- 4 - (- 3))^{2} + 4

\frac{x - 5}{x + 2} \geq 0

2 x^{2} + 7 x - 15 \geq 0

\frac{( x + 2 )}{x - 1} \leq 0

What is (-6x^8y^{-6}z^0)/(1x^{-1)y^{-6}z^5} ?
The solution to (-6x^8y^{-6}z^0)/(1x^{-1)y^{-6}z^5} is -(6x^9)/(z^5)