What are the solutions to the equation 3(x-2)^2+4=79 ?

The solutions to the equation 3(x-2)^2+4=79 are x=7,x=-3

Find the zeros of 3(x-2)^2+4=79

The zeros of 3(x-2)^2+4=79 are x=7,x=-3

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3 (x - 2)^{2} + 4 = 79

x = 7, x = - 3

Solution steps

3 (x - 2)^{2} + 4 = 79

Move

4

to the right side

3 (x - 2)^{2} = 75

Divide both sides by

3

(x - 2)^{2} = 25

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = 25 : x = 7

Solve

x - 2 = - 25 : x = - 3

The solutions to the quadratic equation are:

x = 7, x = - 3

3 x^{4} - 21 x^{3} + 10 x^{2}

4 a x (a x - y) - (a x - y)^{2} - 4 (a x - y)

e^{7} = x

4 (\frac{3}{5} (\frac{4}{7} - \frac{3}{5}) - (\frac{5}{4} + \frac{2}{3}) \frac{3}{2})

What are the solutions to the equation 3(x-2)^2+4=79 ?
The solutions to the equation 3(x-2)^2+4=79 are x=7,x=-3
Find the zeros of 3(x-2)^2+4=79
The zeros of 3(x-2)^2+4=79 are x=7,x=-3