What are the solutions to the equation 2a^2+72=0 ?

The solutions to the equation 2a^2+72=0 are a=6i,a=-6i

Find the zeros of 2a^2+72=0

The zeros of 2a^2+72=0 are a=6i,a=-6i

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2 a^{2} + 72 = 0

a = 6 i, a = - 6 i

Solution steps

2 a^{2} + 72 = 0

Move

72

to the right side

2 a^{2} = - 72

Divide both sides by

2

a^{2} = - 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = - 36, a = - - 36

- 36 = 6 i

- - 36 = - 6 i

a = 6 i, a = - 6 i

a^{2} - 15 ab + 26 b^{2}

x^{2} - x = - 2

3 x^{2} - 36 x + 81 = 0

e^{2^{2}}

4 (0) + y = 5

What are the solutions to the equation 2a^2+72=0 ?
The solutions to the equation 2a^2+72=0 are a=6i,a=-6i
Find the zeros of 2a^2+72=0
The zeros of 2a^2+72=0 are a=6i,a=-6i