What are the solutions to the equation 2x^2-5x=-3 ?

The solutions to the equation 2x^2-5x=-3 are x= 3/2 ,x=1

Find the zeros of 2x^2-5x=-3

The zeros of 2x^2-5x=-3 are x= 3/2 ,x=1

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2 x^{2} - 5 x = - 3

x = \frac{3}{2}, x = 1

Decimal Notation

x = 1.5, x = 1

Solution steps

2 x^{2} - 5 x = - 3

Move

3

to the left side

2 x^{2} - 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 \cdot 3 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 2}

x = \frac{- ( - 5 ) + 1}{2 \cdot 2} : \frac{3}{2}

x = \frac{- ( - 5 ) - 1}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = 1

- 4 - (- 8)

(2)^{4}

3 x^{2} + 3 x + 3

- 2 x^{2} + 6 x

10 x^{2} - 32 x + 24

What are the solutions to the equation 2x^2-5x=-3 ?
The solutions to the equation 2x^2-5x=-3 are x= 3/2 ,x=1
Find the zeros of 2x^2-5x=-3
The zeros of 2x^2-5x=-3 are x= 3/2 ,x=1