What is ((4x-3))/2 >((x+8))/4 ?

The solution to ((4x-3))/2 >((x+8))/4 is x>2

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((4x-3))/2 >((x+8))/4

\frac{( 4 x - 3 )}{2} > \frac{( x + 8 )}{4}

x > 2

Interval Notation

(2, \infty)

Solution steps

\frac{( 4 x - 3 )}{2} > \frac{( x + 8 )}{4}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(4 x - 3) \cdot 4 > 2 (x + 8)

Expand

(4 x - 3) \cdot 4 : 16 x - 12

Expand

2 (x + 8) : 2 x + 16

16 x - 12 > 2 x + 16

Move

12

to the right side

16 x > 2 x + 28

Move

2 x

to the left side

14 x > 28

Divide both sides by

14

x > 2

x^{2} > 3 x - 2

2 t + 2 = 10

2 x - 3 (x - 4) = x + 2

r^{2} = \frac{100}{2 - 3}

4 x^{2} + 56 = 20