What are the solutions to the equation 8x^2+56x=0 ?

The solutions to the equation 8x^2+56x=0 are x=0,x=-7

Find the zeros of 8x^2+56x=0

The zeros of 8x^2+56x=0 are x=0,x=-7

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8 x^{2} + 56 x = 0

x = 0, x = - 7

Solution steps

8 x^{2} + 56 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 56 \pm 5 6 ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

5 6^{2} - 4 \cdot 8 \cdot 0 = 56

x_{1, 2} = \frac{- 56 \pm 56}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 56 + 56}{2 \cdot 8}, x_{2} = \frac{- 56 - 56}{2 \cdot 8}

x = \frac{- 56 + 56}{2 \cdot 8} : 0

x = \frac{- 56 - 56}{2 \cdot 8} : - 7

The solutions to the quadratic equation are:

x = 0, x = - 7

28 n^{4} + 16 n^{3} - 80 n^{2}

4 v + 1 - 7 (- 2 v - 1) = 2 (v - 3)

27 b^{3} + 1

x^{2} - 4 x y + 4 y^{2}

5 - \frac{12}{3}

What are the solutions to the equation 8x^2+56x=0 ?
The solutions to the equation 8x^2+56x=0 are x=0,x=-7
Find the zeros of 8x^2+56x=0
The zeros of 8x^2+56x=0 are x=0,x=-7