What are the solutions to the equation (v-4)^2-72=0 ?

The solutions to the equation (v-4)^2-72=0 are v=6sqrt(2)+4,v=-6sqrt(2)+4

Find the zeros of (v-4)^2-72=0

The zeros of (v-4)^2-72=0 are v=6sqrt(2)+4,v=-6sqrt(2)+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(v - 4)^{2} - 72 = 0

v = 62 + 4, v = - 62 + 4

Decimal Notation

v = 12.48528 \dots, v = - 4.48528 \dots

Solution steps

(v - 4)^{2} - 72 = 0

Move

72

to the right side

(v - 4)^{2} = 72

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

v - 4 = 72 : v = 62 + 4

Solve

v - 4 = - 72 : v = - 62 + 4

The solutions to the quadratic equation are:

v = 62 + 4, v = - 62 + 4

x^{2} + 12 x + 22 = 0

0.0034 t^{2} - 0.52518 t + 20 = 5

2 \cdot ∣ x + 1 ∣ = 10

3 y^{2} = - y + 2

x^{3} - 4 x^{2} + 25 x - 100

What are the solutions to the equation (v-4)^2-72=0 ?
The solutions to the equation (v-4)^2-72=0 are v=6sqrt(2)+4,v=-6sqrt(2)+4
Find the zeros of (v-4)^2-72=0
The zeros of (v-4)^2-72=0 are v=6sqrt(2)+4,v=-6sqrt(2)+4