What are the solutions to the equation 15w^2+4w-1=2w ?

The solutions to the equation 15w^2+4w-1=2w are w= 1/5 ,w=-1/3

Find the zeros of 15w^2+4w-1=2w

The zeros of 15w^2+4w-1=2w are w= 1/5 ,w=-1/3

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15 w^{2} + 4 w - 1 = 2 w

w = \frac{1}{5}, w = - \frac{1}{3}

Decimal Notation

w = 0.2, w = - 0.33333 \dots

Solution steps

15 w^{2} + 4 w - 1 = 2 w

Move

2 w

to the left side

15 w^{2} + 2 w - 1 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 15 ( - 1 )}{2 \cdot 15}

2^{2} - 4 \cdot 15 (- 1) = 8

w_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 15}

Separate the solutions

w_{1} = \frac{- 2 + 8}{2 \cdot 15}, w_{2} = \frac{- 2 - 8}{2 \cdot 15}

w = \frac{- 2 + 8}{2 \cdot 15} : \frac{1}{5}

w = \frac{- 2 - 8}{2 \cdot 15} : - \frac{1}{3}

The solutions to the quadratic equation are:

w = \frac{1}{5}, w = - \frac{1}{3}

(\frac{5}{8})^{4} \cdot (\frac{5}{8})^{5} \cdot (\frac{5}{8})^{6}

s^{2} - 6 s + 9 = 0

8 x - 5 = - 2 x^{2}

5 + \frac{n}{2} > 8

- 2 lo g_{3} (x) + 2 \leq 10

What are the solutions to the equation 15w^2+4w-1=2w ?
The solutions to the equation 15w^2+4w-1=2w are w= 1/5 ,w=-1/3
Find the zeros of 15w^2+4w-1=2w
The zeros of 15w^2+4w-1=2w are w= 1/5 ,w=-1/3