What are the solutions to the equation 0=x^2+2x+3 ?

The solutions to the equation 0=x^2+2x+3 are x=-1+sqrt(2)i,x=-1-sqrt(2)i

Find the zeros of 0=x^2+2x+3

The zeros of 0=x^2+2x+3 are x=-1+sqrt(2)i,x=-1-sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} + 2 x + 3

x = - 1 + 2 i, x = - 1 - 2 i

Solution steps

0 = x^{2} + 2 x + 3

Switch sides

x^{2} + 2 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 3 : 22 i

x_{1, 2} = \frac{- 2 \pm 2 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 2 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 2 i}{2 \cdot 1}

x = \frac{- 2 + 2 2 i}{2 \cdot 1} : - 1 + 2 i

x = \frac{- 2 - 2 2 i}{2 \cdot 1} : - 1 - 2 i

The solutions to the quadratic equation are:

x = - 1 + 2 i, x = - 1 - 2 i

(t)^{2} + (3 t)^{2} = 4

5 t + 1 > 3 t - 13

4 t^{2} + 13 t + 10

12 \geq 6 (12 x + 2)

- 5 y^{2} + 3 y + 14

What are the solutions to the equation 0=x^2+2x+3 ?
The solutions to the equation 0=x^2+2x+3 are x=-1+sqrt(2)i,x=-1-sqrt(2)i
Find the zeros of 0=x^2+2x+3
The zeros of 0=x^2+2x+3 are x=-1+sqrt(2)i,x=-1-sqrt(2)i