What are the solutions to the equation 2x^2+7x-1=0 ?

The solutions to the equation 2x^2+7x-1=0 are x=(-7+sqrt(57))/4 ,x=(-7-sqrt(57))/4

Find the zeros of 2x^2+7x-1=0

The zeros of 2x^2+7x-1=0 are x=(-7+sqrt(57))/4 ,x=(-7-sqrt(57))/4

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2 x^{2} + 7 x - 1 = 0

x = \frac{- 7 + 57}{4}, x = \frac{- 7 - 57}{4}

Decimal Notation

x = 0.13745 \dots, x = - 3.63745 \dots

Solution steps

2 x^{2} + 7 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 1) = 57

x_{1, 2} = \frac{- 7 \pm 57}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 57}{2 \cdot 2}, x_{2} = \frac{- 7 - 57}{2 \cdot 2}

x = \frac{- 7 + 57}{2 \cdot 2} : \frac{- 7 + 57}{4}

x = \frac{- 7 - 57}{2 \cdot 2} : \frac{- 7 - 57}{4}

The solutions to the quadratic equation are:

x = \frac{- 7 + 57}{4}, x = \frac{- 7 - 57}{4}

\frac{π}{2} \cdot \frac{π}{2}

\frac{10 !}{6 ! 4 !}

(5 x^{4})^{3}

54 x + 64 \geq 49 x + 59

5 a^{2} + 10 ab - 3 a - 6 b

What are the solutions to the equation 2x^2+7x-1=0 ?
The solutions to the equation 2x^2+7x-1=0 are x=(-7+sqrt(57))/4 ,x=(-7-sqrt(57))/4
Find the zeros of 2x^2+7x-1=0
The zeros of 2x^2+7x-1=0 are x=(-7+sqrt(57))/4 ,x=(-7-sqrt(57))/4