What are the solutions to the equation (4x-9)^2-10(4x-9)+25=0 ?

The solutions to the equation (4x-9)^2-10(4x-9)+25=0 are x= 7/2

Find the zeros of (4x-9)^2-10(4x-9)+25=0

The zeros of (4x-9)^2-10(4x-9)+25=0 are x= 7/2

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(4 x - 9)^{2} - 10 (4 x - 9) + 25 = 0

x = \frac{7}{2}

Decimal Notation

x = 3.5

Solution steps

(4 x - 9)^{2} - 10 (4 x - 9) + 25 = 0

Expand

(4 x - 9)^{2} - 10 (4 x - 9) + 25 : 16 x^{2} - 112 x + 196

16 x^{2} - 112 x + 196 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 112 ) \pm ( - 112 ) ^{2} - 4 \cdot 16 \cdot 196}{2 \cdot 16}

(- 112)^{2} - 4 \cdot 16 \cdot 196 = 0

x_{1, 2} = \frac{- ( - 112 ) \pm 0}{2 \cdot 16}

x = \frac{- ( - 112 )}{2 \cdot 16}

\frac{- ( - 112 )}{2 \cdot 16} = \frac{7}{2}

x = \frac{7}{2}

The solution to the quadratic equation is:

x = \frac{7}{2}

9 x^{2} + x + 11 = 0

w^{2} = 0

lo g_{e} (1)

x - 7 = 2 x - 1

\frac{1}{36} x^{2} - 25 = 0

What are the solutions to the equation (4x-9)^2-10(4x-9)+25=0 ?
The solutions to the equation (4x-9)^2-10(4x-9)+25=0 are x= 7/2
Find the zeros of (4x-9)^2-10(4x-9)+25=0
The zeros of (4x-9)^2-10(4x-9)+25=0 are x= 7/2