What are the solutions to the equation 25c^2-5c-16=-4 ?

The solutions to the equation 25c^2-5c-16=-4 are c= 4/5 ,c=-3/5

Find the zeros of 25c^2-5c-16=-4

The zeros of 25c^2-5c-16=-4 are c= 4/5 ,c=-3/5

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25 c^{2} - 5 c - 16 = - 4

c = \frac{4}{5}, c = - \frac{3}{5}

Decimal Notation

c = 0.8, c = - 0.6

Solution steps

25 c^{2} - 5 c - 16 = - 4

Move

4

to the left side

25 c^{2} - 5 c - 12 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 25 ( - 12 )}{2 \cdot 25}

(- 5)^{2} - 4 \cdot 25 (- 12) = 35

c_{1, 2} = \frac{- ( - 5 ) \pm 35}{2 \cdot 25}

Separate the solutions

c_{1} = \frac{- ( - 5 ) + 35}{2 \cdot 25}, c_{2} = \frac{- ( - 5 ) - 35}{2 \cdot 25}

c = \frac{- ( - 5 ) + 35}{2 \cdot 25} : \frac{4}{5}

c = \frac{- ( - 5 ) - 35}{2 \cdot 25} : - \frac{3}{5}

The solutions to the quadratic equation are:

c = \frac{4}{5}, c = - \frac{3}{5}

∣ 7 x + 1 ∣ = ∣ 2 x + 11 ∣

- 3 x^{2} + 18 x + 165 = 0

\frac{- 1 + 1}{2}

4 x + 1 = 2 (2 x + 3)

- 3 = - x

What are the solutions to the equation 25c^2-5c-16=-4 ?
The solutions to the equation 25c^2-5c-16=-4 are c= 4/5 ,c=-3/5
Find the zeros of 25c^2-5c-16=-4
The zeros of 25c^2-5c-16=-4 are c= 4/5 ,c=-3/5