What are the solutions to the equation 5x^2+4=7 ?

The solutions to the equation 5x^2+4=7 are x=sqrt(3/5),x=-sqrt(3/5)

Find the zeros of 5x^2+4=7

The zeros of 5x^2+4=7 are x=sqrt(3/5),x=-sqrt(3/5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} + 4 = 7

x = \frac{3}{5}, x = - \frac{3}{5}

Decimal Notation

x = 0.77459 \dots, x = - 0.77459 \dots

Solution steps

5 x^{2} + 4 = 7

Move

4

to the right side

5 x^{2} = 3

Divide both sides by

5

x^{2} = \frac{3}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{3}{5}, x = - \frac{3}{5}

4 (- x - 1) + 5 x - 2 = - 2 x - x

3 2^{\frac{- 3}{5}}

3 p^{2} + 3 = 10 p

- 5 b^{4} + 10 b^{3} - 25 b

b^{2} - 1

What are the solutions to the equation 5x^2+4=7 ?
The solutions to the equation 5x^2+4=7 are x=sqrt(3/5),x=-sqrt(3/5)
Find the zeros of 5x^2+4=7
The zeros of 5x^2+4=7 are x=sqrt(3/5),x=-sqrt(3/5)