What are the solutions to the equation z^2+z-6=0 ?

The solutions to the equation z^2+z-6=0 are z=2,z=-3

Find the zeros of z^2+z-6=0

The zeros of z^2+z-6=0 are z=2,z=-3

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z^{2} + z - 6 = 0

z = 2, z = - 3

Solution steps

z^{2} + z - 6 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 6) = 5

z_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 1 + 5}{2 \cdot 1}, z_{2} = \frac{- 1 - 5}{2 \cdot 1}

z = \frac{- 1 + 5}{2 \cdot 1} : 2

z = \frac{- 1 - 5}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

z = 2, z = - 3

3 x + 4 = 6 (5 x - 5) + 88

3 6^{2} + b^{2} = 8 5^{2}

48 x - 24 x^{2} + 3 x^{3}

- \frac{10 ( - 1 ) + 3}{( 5 ( - 1 ) ^{2} + 3 ( - 1 ) ) ^{2}}

0.25 x^{2} - x + 1.5 = 0

What are the solutions to the equation z^2+z-6=0 ?
The solutions to the equation z^2+z-6=0 are z=2,z=-3
Find the zeros of z^2+z-6=0
The zeros of z^2+z-6=0 are z=2,z=-3