What are the solutions to the equation x^2+13x=-12 ?

The solutions to the equation x^2+13x=-12 are x=-1,x=-12

Find the zeros of x^2+13x=-12

The zeros of x^2+13x=-12 are x=-1,x=-12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 13 x = - 12

x = - 1, x = - 12

Solution steps

x^{2} + 13 x = - 12

Move

12

to the left side

x^{2} + 13 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot 12 = 11

x_{1, 2} = \frac{- 13 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 11}{2 \cdot 1}, x_{2} = \frac{- 13 - 11}{2 \cdot 1}

x = \frac{- 13 + 11}{2 \cdot 1} : - 1

x = \frac{- 13 - 11}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = - 1, x = - 12

5 (3 y - 1) - 3 (2 y) = 10

3 (x - 2) < 2 (x + 9)

\frac{1}{2} (3) + 2

5 - 3 a < - 10

ln (44) = 3.78

What are the solutions to the equation x^2+13x=-12 ?
The solutions to the equation x^2+13x=-12 are x=-1,x=-12
Find the zeros of x^2+13x=-12
The zeros of x^2+13x=-12 are x=-1,x=-12