What are the solutions to the equation 2a^2-a+[2(a-1)(a+3)]=26 ?

The solutions to the equation 2a^2-a+[2(a-1)(a+3)]=26 are a=(-3+sqrt(521))/8 ,a=(-3-sqrt(521))/8

Find the zeros of 2a^2-a+[2(a-1)(a+3)]=26

The zeros of 2a^2-a+[2(a-1)(a+3)]=26 are a=(-3+sqrt(521))/8 ,a=(-3-sqrt(521))/8

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2 a^{2} - a + [2 (a - 1) (a + 3)] = 26

a = \frac{- 3 + 521}{8}, a = \frac{- 3 - 521}{8}

Decimal Notation

a = 2.47817 \dots, a = - 3.22817 \dots

Solution steps

2 a^{2} - a + [2 (a - 1) (a + 3)] = 26

Expand

2 a^{2} - a + (2 (a - 1) (a + 3)) : 4 a^{2} + 3 a - 6

4 a^{2} + 3 a - 6 = 26

Move

26

to the left side

4 a^{2} + 3 a - 32 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 32 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 32) = 521

a_{1, 2} = \frac{- 3 \pm 521}{2 \cdot 4}

Separate the solutions

a_{1} = \frac{- 3 + 521}{2 \cdot 4}, a_{2} = \frac{- 3 - 521}{2 \cdot 4}

a = \frac{- 3 + 521}{2 \cdot 4} : \frac{- 3 + 521}{8}

a = \frac{- 3 - 521}{2 \cdot 4} : \frac{- 3 - 521}{8}

The solutions to the quadratic equation are:

a = \frac{- 3 + 521}{8}, a = \frac{- 3 - 521}{8}

2 b^{3} - 24 + 16 b - 3 b^{2}

3 (1)^{\frac{1}{3}}

a^{2} b + a b^{2} + 3 a + 3 b

\frac{b}{6} > 14

x^{3} - 5 x^{2} - 14 x

What are the solutions to the equation 2a^2-a+[2(a-1)(a+3)]=26 ?
The solutions to the equation 2a^2-a+[2(a-1)(a+3)]=26 are a=(-3+sqrt(521))/8 ,a=(-3-sqrt(521))/8
Find the zeros of 2a^2-a+[2(a-1)(a+3)]=26
The zeros of 2a^2-a+[2(a-1)(a+3)]=26 are a=(-3+sqrt(521))/8 ,a=(-3-sqrt(521))/8