What are the solutions to the equation 2x^2-6=-x ?

The solutions to the equation 2x^2-6=-x are x= 3/2 ,x=-2

Find the zeros of 2x^2-6=-x

The zeros of 2x^2-6=-x are x= 3/2 ,x=-2

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2 x^{2} - 6 = - x

x = \frac{3}{2}, x = - 2

Decimal Notation

x = 1.5, x = - 2

Solution steps

2 x^{2} - 6 = - x

Move

x

to the left side

2 x^{2} - 6 + x = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 6) = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 \cdot 2}, x_{2} = \frac{- 1 - 7}{2 \cdot 2}

x = \frac{- 1 + 7}{2 \cdot 2} : \frac{3}{2}

x = \frac{- 1 - 7}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 2

4 x^{2} y^{2} - 1

x + 10 \geq - \frac{21}{x}

15 x y - 10 x + 12 y - 8

0^{\frac{1}{3}}

\frac{250}{2.87 \cdot 1 0 ^{8}}

What are the solutions to the equation 2x^2-6=-x ?
The solutions to the equation 2x^2-6=-x are x= 3/2 ,x=-2
Find the zeros of 2x^2-6=-x
The zeros of 2x^2-6=-x are x= 3/2 ,x=-2