What are the solutions to the equation 4x^2+2x+1=0 ?

The solutions to the equation 4x^2+2x+1=0 are x=-1/4+i(sqrt(3))/4 ,x=-1/4-i(sqrt(3))/4

Find the zeros of 4x^2+2x+1=0

The zeros of 4x^2+2x+1=0 are x=-1/4+i(sqrt(3))/4 ,x=-1/4-i(sqrt(3))/4

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4 x^{2} + 2 x + 1 = 0

x = - \frac{1}{4} + i \frac{3}{4}, x = - \frac{1}{4} - i \frac{3}{4}

Solution steps

4 x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

Simplify

2^{2} - 4 \cdot 4 \cdot 1 : 23 i

x_{1, 2} = \frac{- 2 \pm 2 3 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 2 + 2 3 i}{2 \cdot 4}, x_{2} = \frac{- 2 - 2 3 i}{2 \cdot 4}

x = \frac{- 2 + 2 3 i}{2 \cdot 4} : - \frac{1}{4} + i \frac{3}{4}

x = \frac{- 2 - 2 3 i}{2 \cdot 4} : - \frac{1}{4} - i \frac{3}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4} + i \frac{3}{4}, x = - \frac{1}{4} - i \frac{3}{4}

- \frac{v}{2} + 6 = 14

x^{2} - 49 x = 0

∣ x + 3 ∣ > 10

\frac{7 \cdot 3 ^{- 2}}{2 ^{- 2} \cdot 3 ^{- 1}}

K (r, s) = 9 r - s

What are the solutions to the equation 4x^2+2x+1=0 ?
The solutions to the equation 4x^2+2x+1=0 are x=-1/4+i(sqrt(3))/4 ,x=-1/4-i(sqrt(3))/4
Find the zeros of 4x^2+2x+1=0
The zeros of 4x^2+2x+1=0 are x=-1/4+i(sqrt(3))/4 ,x=-1/4-i(sqrt(3))/4