What is x^3-6x^2+3x+5>= x^3-7x^2-x+10 ?

The solution to x^3-6x^2+3x+5>= x^3-7x^2-x+10 is x = 1

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x^3-6x^2+3x+5>= x^3-7x^2-x+10

x^{3} - 6 x^{2} + 3 x + 5 \geq x^{3} - 7 x^{2} - x + 10

x \leq - 5 or x \geq 1

Interval Notation

(- \infty, - 5] \cup [1, \infty)

Solution steps

x^{3} - 6 x^{2} + 3 x + 5 \geq x^{3} - 7 x^{2} - x + 10

Rewrite in standard form

x^{2} + 4 x - 5 \geq 0

Factor

x^{2} + 4 x - 5 : (x - 1) (x + 5)

(x - 1) (x + 5) \geq 0

Identify the intervals

x \leq - 5 or x \geq 1

(1 \frac{9}{16})^{\frac{3}{2}}

c x^{2} + c y^{2} - w x^{2} - w y^{2} + w - c

15 x^{2} - 8 x - 12

\frac{2}{x - 1} \geq - 1

\frac{5 ( x - 4 )}{2} \geq \frac{2 x}{3} - 15

What is x^3-6x^2+3x+5>= x^3-7x^2-x+10 ?
The solution to x^3-6x^2+3x+5>= x^3-7x^2-x+10 is x<=-5\lor x>= 1