What are the solutions to the equation 4x^2+12x=-12 ?

The solutions to the equation 4x^2+12x=-12 are x=-3/2+i(sqrt(3))/2 ,x=-3/2-i(sqrt(3))/2

Find the zeros of 4x^2+12x=-12

The zeros of 4x^2+12x=-12 are x=-3/2+i(sqrt(3))/2 ,x=-3/2-i(sqrt(3))/2

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4 x^{2} + 12 x = - 12

x = - \frac{3}{2} + i \frac{3}{2}, x = - \frac{3}{2} - i \frac{3}{2}

Solution steps

4 x^{2} + 12 x = - 12

Move

12

to the left side

4 x^{2} + 12 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 \cdot 12}{2 \cdot 4}

Simplify

1 2^{2} - 4 \cdot 4 \cdot 12 : 43 i

x_{1, 2} = \frac{- 12 \pm 4 3 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 4 3 i}{2 \cdot 4}, x_{2} = \frac{- 12 - 4 3 i}{2 \cdot 4}

x = \frac{- 12 + 4 3 i}{2 \cdot 4} : - \frac{3}{2} + i \frac{3}{2}

x = \frac{- 12 - 4 3 i}{2 \cdot 4} : - \frac{3}{2} - i \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{3}{2}, x = - \frac{3}{2} - i \frac{3}{2}

\frac{2}{3} + \frac{5}{6} - \frac{1}{12}

2 ∣ 7 - z ∣ - 3 \geq 13

6 x + 2 = 29 - 3 x

∣ 2 x - 5 ∣ = 8

\frac{3 π}{8} - \frac{π}{8}

What are the solutions to the equation 4x^2+12x=-12 ?
The solutions to the equation 4x^2+12x=-12 are x=-3/2+i(sqrt(3))/2 ,x=-3/2-i(sqrt(3))/2
Find the zeros of 4x^2+12x=-12
The zeros of 4x^2+12x=-12 are x=-3/2+i(sqrt(3))/2 ,x=-3/2-i(sqrt(3))/2