What are the solutions to the equation x^2+2x-57=x-1 ?

The solutions to the equation x^2+2x-57=x-1 are x=7,x=-8

Find the zeros of x^2+2x-57=x-1

The zeros of x^2+2x-57=x-1 are x=7,x=-8

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x^{2} + 2 x - 57 = x - 1

x = 7, x = - 8

Solution steps

x^{2} + 2 x - 57 = x - 1

Move

1

to the left side

x^{2} + 2 x - 56 = x

Move

x

to the left side

x^{2} + x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 56) = 15

x_{1, 2} = \frac{- 1 \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 15}{2 \cdot 1}, x_{2} = \frac{- 1 - 15}{2 \cdot 1}

x = \frac{- 1 + 15}{2 \cdot 1} : 7

x = \frac{- 1 - 15}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 7, x = - 8

3 (x - 5) = x + 11

(- 2 - 2)^{3}

35 + 30 x

2 n + 6 = 18

15 k + 13 \leq - 17

What are the solutions to the equation x^2+2x-57=x-1 ?
The solutions to the equation x^2+2x-57=x-1 are x=7,x=-8
Find the zeros of x^2+2x-57=x-1
The zeros of x^2+2x-57=x-1 are x=7,x=-8