What are the solutions to the equation 2x^2=48-10x ?

The solutions to the equation 2x^2=48-10x are x=3,x=-8

Find the zeros of 2x^2=48-10x

The zeros of 2x^2=48-10x are x=3,x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} = 48 - 10 x

x = 3, x = - 8

Solution steps

2 x^{2} = 48 - 10 x

Move

10 x

to the left side

2 x^{2} + 10 x = 48

Move

48

to the left side

2 x^{2} + 10 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 48 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 48) = 22

x_{1, 2} = \frac{- 10 \pm 22}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 22}{2 \cdot 2}, x_{2} = \frac{- 10 - 22}{2 \cdot 2}

x = \frac{- 10 + 22}{2 \cdot 2} : 3

x = \frac{- 10 - 22}{2 \cdot 2} : - 8

The solutions to the quadratic equation are:

x = 3, x = - 8

1 3^{- 1} \cdot 1 3^{3}

x^{4} - 3 x^{3} + 6 x^{2} - 12 x + 8

\frac{4}{\frac{3}{\frac{8}{9}}}

(3 d^{2})^{0}

2 \frac{\frac{1}{2}}{5} = \frac{p}{4}

What are the solutions to the equation 2x^2=48-10x ?
The solutions to the equation 2x^2=48-10x are x=3,x=-8
Find the zeros of 2x^2=48-10x
The zeros of 2x^2=48-10x are x=3,x=-8