What is (15x^3y^5)/(2xy)*(6xy^3)/(9x^4y) ?

The solution to (15x^3y^5)/(2xy)*(6xy^3)/(9x^4y) is (5y^6)/x

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simplify (15x^3y^5)/(2xy)*(6xy^3)/(9x^4y)

simplify

\frac{15 x ^{3} y ^{5}}{2 x y} \cdot \frac{6 x y ^{3}}{9 x ^{4} y}

\frac{5 y ^{6}}{x}

Solution steps

\frac{15 x ^{3} y ^{5}}{2 x y} \cdot \frac{6 x y ^{3}}{9 x ^{4} y}

Cancel

\frac{15 x ^{3} y ^{5}}{2 x y} : \frac{15 x ^{2} y ^{4}}{2}

= \frac{15 x ^{2} y ^{4}}{2} \cdot \frac{6 x y ^{3}}{9 x ^{4} y}

Cancel

\frac{6 x y ^{3}}{9 x ^{4} y} : \frac{2 y ^{2}}{3 x ^{3}}

= \frac{15 x ^{2} y ^{4}}{2} \cdot \frac{2 y ^{2}}{3 x ^{3}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{15 x ^{2} y ^{4} \cdot 2 y ^{2}}{2 \cdot 3 x ^{3}}

Cancel the common factor:

2

= \frac{15 x ^{2} y ^{4} y ^{2}}{3 x ^{3}}

Factor the number:

15 = 3 \cdot 5

= \frac{3 \cdot 5 x ^{2} y ^{4} y ^{2}}{3 x ^{3}}

Cancel the common factor:

3

= \frac{5 x ^{2} y ^{4} y ^{2}}{x ^{3}}

Simplify

\frac{x ^{2}}{x ^{3}} : \frac{1}{x}

= \frac{5 y ^{4} y ^{2}}{x}

Simplify

y^{4} y^{2} : y^{6}

= \frac{5 y ^{6}}{x}

4 v = 28

5 x^{2} + 3 x - 8 = 0

\frac{x}{8} + \frac{x}{3} = \frac{3}{16}

125 y^{3} - 8 x^{3}

2 x - 3 = x + 4

What is (15x^3y^5)/(2xy)*(6xy^3)/(9x^4y) ?
The solution to (15x^3y^5)/(2xy)*(6xy^3)/(9x^4y) is (5y^6)/x