What are the solutions to the equation -1=x^2 ?

The solutions to the equation -1=x^2 are x=i,x=-i

Find the zeros of -1=x^2

The zeros of -1=x^2 are x=i,x=-i

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- 1 = x^{2}

x = i, x = - i

Solution steps

- 1 = x^{2}

Switch sides

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

\frac{1}{3} (2 a^{3} b) (6 b^{3})

(\frac{π}{6})^{2}

16 x^{2} + 2 x - 9 = 0

\frac{4}{2 - 2}

3 w^{2} + 12 w = 0

What are the solutions to the equation -1=x^2 ?
The solutions to the equation -1=x^2 are x=i,x=-i
Find the zeros of -1=x^2
The zeros of -1=x^2 are x=i,x=-i