What are the solutions to the equation 8x^2-6x-5=2x^2 ?

The solutions to the equation 8x^2-6x-5=2x^2 are x=(3+sqrt(39))/6 ,x=(3-sqrt(39))/6

Find the zeros of 8x^2-6x-5=2x^2

The zeros of 8x^2-6x-5=2x^2 are x=(3+sqrt(39))/6 ,x=(3-sqrt(39))/6

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8 x^{2} - 6 x - 5 = 2 x^{2}

x = \frac{3 + 39}{6}, x = \frac{3 - 39}{6}

Decimal Notation

x = 1.54083 \dots, x = - 0.54083 \dots

Solution steps

8 x^{2} - 6 x - 5 = 2 x^{2}

Move

2 x^{2}

to the left side

6 x^{2} - 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

(- 6)^{2} - 4 \cdot 6 (- 5) = 239

x_{1, 2} = \frac{- ( - 6 ) \pm 2 39}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 39}{2 \cdot 6}, x_{2} = \frac{- ( - 6 ) - 2 39}{2 \cdot 6}

x = \frac{- ( - 6 ) + 2 39}{2 \cdot 6} : \frac{3 + 39}{6}

x = \frac{- ( - 6 ) - 2 39}{2 \cdot 6} : \frac{3 - 39}{6}

The solutions to the quadratic equation are:

x = \frac{3 + 39}{6}, x = \frac{3 - 39}{6}

3 y^{2} - 15 y + 12

2 x^{2} - 6

5 x^{3} = 135

x^{2} - 2 x = - 8

4 x^{2} - 28 x - 120

What are the solutions to the equation 8x^2-6x-5=2x^2 ?
The solutions to the equation 8x^2-6x-5=2x^2 are x=(3+sqrt(39))/6 ,x=(3-sqrt(39))/6
Find the zeros of 8x^2-6x-5=2x^2
The zeros of 8x^2-6x-5=2x^2 are x=(3+sqrt(39))/6 ,x=(3-sqrt(39))/6