What are the solutions to the equation 16c^2-9=0 ?

The solutions to the equation 16c^2-9=0 are c= 3/4 ,c=-3/4

Find the zeros of 16c^2-9=0

The zeros of 16c^2-9=0 are c= 3/4 ,c=-3/4

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16 c^{2} - 9 = 0

c = \frac{3}{4}, c = - \frac{3}{4}

Decimal Notation

c = 0.75, c = - 0.75

Solution steps

16 c^{2} - 9 = 0

Move

9

to the right side

16 c^{2} = 9

Divide both sides by

16

c^{2} = \frac{9}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = \frac{9}{16}, c = - \frac{9}{16}

\frac{9}{16} = \frac{3}{4}

- \frac{9}{16} = - \frac{3}{4}

c = \frac{3}{4}, c = - \frac{3}{4}

2 x^{2} + 2 x - 5 = 0

(8 a^{- 3} b^{9})^{\frac{2}{3}}

9 x^{2} = 36

\frac{2 ^{3}}{2 ^{- 4}}

∣ 2 x + 3 ∣ = 2 x + 3

What are the solutions to the equation 16c^2-9=0 ?
The solutions to the equation 16c^2-9=0 are c= 3/4 ,c=-3/4
Find the zeros of 16c^2-9=0
The zeros of 16c^2-9=0 are c= 3/4 ,c=-3/4