What are the solutions to the equation 6x^2-8x+3=0 ?

The solutions to the equation 6x^2-8x+3=0 are x= 2/3+i(sqrt(2))/6 ,x= 2/3-i(sqrt(2))/6

Find the zeros of 6x^2-8x+3=0

The zeros of 6x^2-8x+3=0 are x= 2/3+i(sqrt(2))/6 ,x= 2/3-i(sqrt(2))/6

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6 x^{2} - 8 x + 3 = 0

x = \frac{2}{3} + i \frac{2}{6}, x = \frac{2}{3} - i \frac{2}{6}

Solution steps

6 x^{2} - 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 6 \cdot 3}{2 \cdot 6}

Simplify

(- 8)^{2} - 4 \cdot 6 \cdot 3 : 22 i

x_{1, 2} = \frac{- ( - 8 ) \pm 2 2 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 2 i}{2 \cdot 6}, x_{2} = \frac{- ( - 8 ) - 2 2 i}{2 \cdot 6}

x = \frac{- ( - 8 ) + 2 2 i}{2 \cdot 6} : \frac{2}{3} + i \frac{2}{6}

x = \frac{- ( - 8 ) - 2 2 i}{2 \cdot 6} : \frac{2}{3} - i \frac{2}{6}

The solutions to the quadratic equation are:

x = \frac{2}{3} + i \frac{2}{6}, x = \frac{2}{3} - i \frac{2}{6}

lo g_{4} (16)

(e^{x})^{\frac{1}{2}}

x^{4} - 12 x^{2} + 36

5 = \frac{1}{3} (5 x - 15)

- 8 x + 3 x^{2} = 18

What are the solutions to the equation 6x^2-8x+3=0 ?
The solutions to the equation 6x^2-8x+3=0 are x= 2/3+i(sqrt(2))/6 ,x= 2/3-i(sqrt(2))/6
Find the zeros of 6x^2-8x+3=0
The zeros of 6x^2-8x+3=0 are x= 2/3+i(sqrt(2))/6 ,x= 2/3-i(sqrt(2))/6