What are the solutions to the equation x^2-x-56=0 ?

The solutions to the equation x^2-x-56=0 are x=8,x=-7

Find the zeros of x^2-x-56=0

The zeros of x^2-x-56=0 are x=8,x=-7

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x^{2} - x - 56 = 0

x = 8, x = - 7

Solution steps

x^{2} - x - 56 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 56 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 56) = 15

x_{1, 2} = \frac{- ( - 1 ) \pm 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 15}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 15}{2 \cdot 1}

x = \frac{- ( - 1 ) + 15}{2 \cdot 1} : 8

x = \frac{- ( - 1 ) - 15}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 8, x = - 7

0.75 (160) = \frac{s ^{2}}{30.2 5 ^{2}}

(343 x^{9})^{\frac{2}{3}}

- 5 (n + 10) + 5 n

- y = 2 - y^{2}

9 - 2 x < 7 + 2 (x - 3)

What are the solutions to the equation x^2-x-56=0 ?
The solutions to the equation x^2-x-56=0 are x=8,x=-7
Find the zeros of x^2-x-56=0
The zeros of x^2-x-56=0 are x=8,x=-7