What is (x+1)(x+2)(x+3)<= 0 ?

The solution to (x+1)(x+2)(x+3)<= 0 is x<=-3\lor-2<= x<=-1

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(x+1)(x+2)(x+3)<= 0

(x + 1) (x + 2) (x + 3) \leq 0

x \leq - 3 or - 2 \leq x \leq - 1

Interval Notation

(- \infty, - 3] \cup [- 2, - 1]

Solution steps

(x + 1) (x + 2) (x + 3) \leq 0

Identify the intervals

x \leq - 3 or - 2 \leq x \leq - 1

\frac{180 ( 250 + 491.67 )}{500 + 491.67}

6 - 3 [- 7 + x] > 3

\frac{x + \frac{4 x}{y}}{\frac{7}{3 x}}

\frac{5}{7} - \frac{2}{3}

- 9 \cdot 7

What is (x+1)(x+2)(x+3)<= 0 ?
The solution to (x+1)(x+2)(x+3)<= 0 is x<=-3\lor-2<= x<=-1