What are the solutions to the equation z^2+2z=15 ?

The solutions to the equation z^2+2z=15 are z=3,z=-5

Find the zeros of z^2+2z=15

The zeros of z^2+2z=15 are z=3,z=-5

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z^{2} + 2 z = 15

z = 3, z = - 5

Solution steps

z^{2} + 2 z = 15

Move

15

to the left side

z^{2} + 2 z - 15 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 15) = 8

z_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 2 + 8}{2 \cdot 1}, z_{2} = \frac{- 2 - 8}{2 \cdot 1}

z = \frac{- 2 + 8}{2 \cdot 1} : 3

z = \frac{- 2 - 8}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

z = 3, z = - 5

\frac{1}{8} \cdot \frac{5}{2} + \frac{7}{3} \cdot \frac{3}{4}

a^{6} - 2 a^{3} b^{3} + b^{6}

- \frac{4}{3 ( 8 ) ^{\frac{1}{3}}}

\frac{2}{9} + \frac{1}{7} (\frac{2}{3})^{2}

x^{4} - 16

What are the solutions to the equation z^2+2z=15 ?
The solutions to the equation z^2+2z=15 are z=3,z=-5
Find the zeros of z^2+2z=15
The zeros of z^2+2z=15 are z=3,z=-5