What are the solutions to the equation 18x^2+24x=0 ?

The solutions to the equation 18x^2+24x=0 are x=0,x=-4/3

Find the zeros of 18x^2+24x=0

The zeros of 18x^2+24x=0 are x=0,x=-4/3

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18 x^{2} + 24 x = 0

x = 0, x = - \frac{4}{3}

Solution steps

18 x^{2} + 24 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 18 \cdot 0}{2 \cdot 18}

2 4^{2} - 4 \cdot 18 \cdot 0 = 24

x_{1, 2} = \frac{- 24 \pm 24}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- 24 + 24}{2 \cdot 18}, x_{2} = \frac{- 24 - 24}{2 \cdot 18}

x = \frac{- 24 + 24}{2 \cdot 18} : 0

x = \frac{- 24 - 24}{2 \cdot 18} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = 0, x = - \frac{4}{3}

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21 x - 23 = 23 x - 7

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What are the solutions to the equation 18x^2+24x=0 ?
The solutions to the equation 18x^2+24x=0 are x=0,x=-4/3
Find the zeros of 18x^2+24x=0
The zeros of 18x^2+24x=0 are x=0,x=-4/3