What are the solutions to the equation 3(x+9)^2=36 ?

The solutions to the equation 3(x+9)^2=36 are x=2sqrt(3)-9,x=-2sqrt(3)-9

Find the zeros of 3(x+9)^2=36

The zeros of 3(x+9)^2=36 are x=2sqrt(3)-9,x=-2sqrt(3)-9

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3 (x + 9)^{2} = 36

x = 23 - 9, x = - 23 - 9

Decimal Notation

x = - 5.53589 \dots, x = - 12.46410 \dots

Solution steps

3 (x + 9)^{2} = 36

Divide both sides by

3

(x + 9)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 9 = 12 : x = 23 - 9

Solve

x + 9 = - 12 : x = - 23 - 9

The solutions to the quadratic equation are:

x = 23 - 9, x = - 23 - 9

4 - x = 3

0 = 3 t^{2} - 3

x^{4} + 3 x^{3} + 6 x^{2} + 12 x + 8

2 k^{2} + 4 k + 1 = 0

lo g_{b} (b)

What are the solutions to the equation 3(x+9)^2=36 ?
The solutions to the equation 3(x+9)^2=36 are x=2sqrt(3)-9,x=-2sqrt(3)-9
Find the zeros of 3(x+9)^2=36
The zeros of 3(x+9)^2=36 are x=2sqrt(3)-9,x=-2sqrt(3)-9