What are the solutions to the equation 67t-5t^2=0 ?

The solutions to the equation 67t-5t^2=0 are t=0,t= 67/5

Find the zeros of 67t-5t^2=0

The zeros of 67t-5t^2=0 are t=0,t= 67/5

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67 t - 5 t^{2} = 0

t = 0, t = \frac{67}{5}

Solution steps

67 t - 5 t^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 t^{2} + 67 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 67 \pm 6 7 ^{2} - 4 ( - 5 ) \cdot 0}{2 ( - 5 )}

6 7^{2} - 4 (- 5) \cdot 0 = 67

t_{1, 2} = \frac{- 67 \pm 67}{2 ( - 5 )}

Separate the solutions

t_{1} = \frac{- 67 + 67}{2 ( - 5 )}, t_{2} = \frac{- 67 - 67}{2 ( - 5 )}

t = \frac{- 67 + 67}{2 ( - 5 )} : 0

t = \frac{- 67 - 67}{2 ( - 5 )} : \frac{67}{5}

The solutions to the quadratic equation are:

t = 0, t = \frac{67}{5}

x^{2} - 36 x = 0

\frac{1}{3} - \frac{3}{4}

- x^{3} + 3 x^{2} - 9 x - 13

3 (\frac{x - 1}{2}) = 2 (\frac{3 x + 1}{4})

(x + 8)^{2} (x + 6) > 0

What are the solutions to the equation 67t-5t^2=0 ?
The solutions to the equation 67t-5t^2=0 are t=0,t= 67/5
Find the zeros of 67t-5t^2=0
The zeros of 67t-5t^2=0 are t=0,t= 67/5