What are the solutions to the equation 3t^2-8=0 ?

The solutions to the equation 3t^2-8=0 are t=(2sqrt(2))/(sqrt(3)),t=-(2sqrt(2))/(sqrt(3))

Find the zeros of 3t^2-8=0

The zeros of 3t^2-8=0 are t=(2sqrt(2))/(sqrt(3)),t=-(2sqrt(2))/(sqrt(3))

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3 t^{2} - 8 = 0

t = \frac{2 2}{3}, t = - \frac{2 2}{3}

Solution steps

3 t^{2} - 8 = 0

Move

8

to the right side

3 t^{2} = 8

Divide both sides by

3

t^{2} = \frac{8}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{8}{3}, t = - \frac{8}{3}

\frac{8}{3} = \frac{2 2}{3}

- \frac{8}{3} = - \frac{2 2}{3}

t = \frac{2 2}{3}, t = - \frac{2 2}{3}

- 2 (x - 5) = - 12

\frac{4}{3} - \frac{2}{3}

∣ 8 x - 9 ∣ \leq 14

8^{- \frac{4}{3}}

- 7 < 2 x - 1 \leq - 1

What are the solutions to the equation 3t^2-8=0 ?
The solutions to the equation 3t^2-8=0 are t=(2sqrt(2))/(sqrt(3)),t=-(2sqrt(2))/(sqrt(3))
Find the zeros of 3t^2-8=0
The zeros of 3t^2-8=0 are t=(2sqrt(2))/(sqrt(3)),t=-(2sqrt(2))/(sqrt(3))