What are the solutions to the equation x^2+20x+200=0 ?

The solutions to the equation x^2+20x+200=0 are x=-10+10i,x=-10-10i

Find the zeros of x^2+20x+200=0

The zeros of x^2+20x+200=0 are x=-10+10i,x=-10-10i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 20 x + 200 = 0

x = - 10 + 10 i, x = - 10 - 10 i

Solution steps

x^{2} + 20 x + 200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 200}{2 \cdot 1}

Simplify

2 0^{2} - 4 \cdot 1 \cdot 200 : 20 i

x_{1, 2} = \frac{- 20 \pm 20 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 20 i}{2 \cdot 1}, x_{2} = \frac{- 20 - 20 i}{2 \cdot 1}

x = \frac{- 20 + 20 i}{2 \cdot 1} : - 10 + 10 i

x = \frac{- 20 - 20 i}{2 \cdot 1} : - 10 - 10 i

The solutions to the quadratic equation are:

x = - 10 + 10 i, x = - 10 - 10 i

2 a^{2} - a - 15

5 x^{2} - 3 x - 14

\frac{1}{3} + \frac{1}{15}

\frac{3 ( 5 - c )}{2} = - \frac{2 ( 2 c + 7 )}{3}

- 8 (x + 3) > 2 (x + 4)

What are the solutions to the equation x^2+20x+200=0 ?
The solutions to the equation x^2+20x+200=0 are x=-10+10i,x=-10-10i
Find the zeros of x^2+20x+200=0
The zeros of x^2+20x+200=0 are x=-10+10i,x=-10-10i